Convert the Equation to the Standard Form for a Hyperbola $$\mathrm { y } ^ { 2 } - 16 \mathrm { x } ^ { 2 } - 4 \mathrm { y } + 64 \mathrm { x } - 76 = 0$$

question 92

Multiple Choice

Convert the equation to the standard form for a hyperbola by completing the square on x and y.
- $$\mathrm { y } ^ { 2 } - 16 \mathrm { x } ^ { 2 } - 4 \mathrm { y } + 64 \mathrm { x } - 76 = 0$$

• A) \(\frac { ( y - 2 ) ^ { 2 } } { 16 } - ( x - 2 ) ^ { 2 } = 1\)
• B) \(\frac { ( x - 2 ) ^ { 2 } } { 16 } - ( y - 2 ) ^ { 2 } = 1\)
• C) \(\frac { ( y - 4 ) ^ { 2 } } { 16 } - ( x - 4 ) ^ { 2 } = 1\)
• D) \(( x - 2 ) ^ { 2 } - \frac { ( y - 2 ) ^ { 2 } } { 16 } = 1\)

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