Convert the Equation to the Standard Form for a Hyperbola $$4 x ^ { 2 } - 16 y ^ { 2 } - 16 x - 32 y - 64 = 0$$

question 4

Multiple Choice

Convert the equation to the standard form for a hyperbola by completing the square on x and y.
- $$4 x ^ { 2 } - 16 y ^ { 2 } - 16 x - 32 y - 64 = 0$$

• A) \(\frac { ( x - 2 ) ^ { 2 } } { 16 } - \frac { ( y + 1 ) ^ { 2 } } { 4 } = 1\)
• B) \(\frac { ( x + 2 ) ^ { 2 } } { 16 } - \frac { ( y + 1 ) ^ { 2 } } { 4 } = 1\)
• C) \(\frac { ( x - 2 ) ^ { 2 } } { 16 } - \frac { ( y - 1 ) ^ { 2 } } { 4 } = 1\)
• D) \(\frac { ( x - 2 ) ^ { 2 } } { 4 } - \frac { ( y + 1 ) ^ { 2 } } { 16 } = 1\)

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