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Use the One-To-One Property of Logarithms to Solve Logarithmic Equations log9(5x1)=log9(2x+8)\log _ { 9 } ( 5 x - 1 ) = \log _ { 9 } ( 2 x + 8 )

question 155

Multiple Choice

Use the One-to-One Property of Logarithms to Solve Logarithmic Equations
Solve the logarithmic equation. Be sure to reject any value that is not in the domain of the original logarithmic
expressions. Give the exact answer.
- log9(5x1) =log9(2x+8) \log _ { 9 } ( 5 x - 1 ) = \log _ { 9 } ( 2 x + 8 )


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