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Solve the Equation 1x+4+2x+3=1x2+7x+12\frac { 1 } { x + 4 } + \frac { 2 } { x + 3 } = \frac { - 1 } { x ^ { 2 } + 7 x + 12 }

question 189

Multiple Choice

Solve the equation.
- 1x+4+2x+3=1x2+7x+12\frac { 1 } { x + 4 } + \frac { 2 } { x + 3 } = \frac { - 1 } { x ^ { 2 } + 7 x + 12 }


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