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Solve.
-If y varies inversely as the square of x. If y = 2 when x = 8
Q3: 0.000571 <br>A) <span class="ql-formula" data-value="5.71
Q9: <span class="ql-formula" data-value="( 6,350,000,000 ) \div (
Q20: A number minus 20 times its reciprocal
Q22: <span class="ql-formula" data-value="\begin{array} { l } -
Q52: <span class="ql-formula" data-value="\sqrt [ 4 ] {
Q63: <span class="ql-formula" data-value="( \sqrt { 2 }
Q69: <span class="ql-formula" data-value="x ^ { 2 }
Q150: 16s,24<br>A) 48s <br>B) 16 <br>C) 8s <br>D)
Q174: <span class="ql-formula" data-value="f ( x ) =
Q204: (7 + 8i) - ? = 15