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The Following Output from MINITAB Presents the Results of a Hypothesis

question 103

Multiple Choice

The following output from MINITAB presents the results of a hypothesis test. Test of mu =49vs= 49 \mathrm { vs } . not =49= 49
The assumed standard deviation 10.410.4
N Mean  SE Mean 95%CIZP5846.321.412088(43.5523077,49.0876923) 1.9625260.049701\begin{array}{lcccrr}\mathrm{N} & \text { Mean } & \text { SE Mean } & 95 \% \mathrm{CI} & \mathrm{Z} & \mathrm{P} \\58 & 46.32 & 1.412088 & (43.5523077,49.0876923) & -1.962526 & 0.049701 \\\hline\end{array}


Do you reject H0 at the α=0.01\alpha = 0.01 level?


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