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The Following MINITAB Output Presents a 95% Confidence Interval Find the Sample Size Needed So That the 95% Confidence

question 19

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The following MINITAB output presents a 95% confidence interval.

 The assumed sigma =10.2726 Variable N Mean  SE Mean 95%CIx4648.6111.5146(45.642,51.580) \begin{array}{ccccc}\hline{\text { The assumed sigma }=10.2726} \\\text { Variable } & \mathrm{N} & \text { Mean } & \text { SE Mean } & 95 \% \mathrm{CI} \\\mathrm{x} & 46 & 48.611 & 1.5146 & (45.642,51.580) \\\hline\end{array}

Find the sample size needed so that the 95% confidence interval will have a margin of error of 1.1.


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