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The Following MINITAB Output Presents a 95% Confidence Interval Find the Sample Size Needed So That the 99% Confidence

question 8

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The following MINITAB output presents a 95% confidence interval.  The assumed sigma =8.7500 Variable N Mean  SE Mean 95%CIx4832.9501.2630(30.475,35.425) \begin{array} { c r r c c } \hline { \text { The assumed sigma } = 8.7500 } & \\\\\text { Variable } & \mathrm { N } & \text { Mean } & \text { SE Mean } & 95 \% \mathrm { CI } \\\mathrm { x } & 48 & 32.950 & 1.2630 & ( 30.475,35.425 ) \\\hline\end{array}


Find the sample size needed so that the 99% confidence interval will have a margin of error of 1.3.


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A graphical representation of the market for loanable funds, showing the relationship between the real interest rate and the quantity of loanable funds supplied and demanded.

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