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An octapeptide is subjected to Edman degradation and it is discovered that the amino terminus is
Ser.Treatment of the remaining heptapeptide with BrCN yields a tripeptide
A and a tetrapeptide, B.
The tripeptide A is treated with trypsin, releasing a single residue and a dipeptide.The dipeptide,
on Edman degradation, gives two residues, one of which is not optically active.
The tetrapeptide B is also treated with trypsin, releasing a new tripeptide and a His residue.The
tripeptide from this step is treated with chymotrypsin, resulting in a dipeptide and a single amino
acid.Edman degradation of the dipeptide yields two residues, one of which is Val.
There is no Phe or Trp in the original octapeptide.
Provide a possible sequence of the original octapeptide.
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