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Find the Value of the Test Statistic Z Using Z z=p^ppqnz = \frac { \hat { p } - p } { \sqrt { \frac { p q } { n } } }

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Find the value of the test statistic z using z z=p^ppqnz = \frac { \hat { p } - p } { \sqrt { \frac { p q } { n } } }
-The claim is that the proportion of accidental deaths of the elderly attributable to residential falls is more than 0.10, and the sample statistics include n = 800 deaths of the elderly with 15% of them attributable to residential
Falls.


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