The Probabilities That a Batch of 4 Computers Will Contain $\mu = 0.80$

question 11

Multiple Choice

The probabilities that a batch of 4 computers will contain 0, 1, 2, 3, and 4 defective computers are 0.4096, 0.4096, 0.1536, 0.0256, and 0.0016, respectively. Round answer to the nearest hundredth.

• A) \(\mu = 0.80\)
• B) \(\mu = 1.21\)
• C) \(\mu = 0.70\)
• D) \(\mu = 2.00\)

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