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an Operations Manager Was =30.71.84= 30.7 - 1.84

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An operations manager was interested in determining if there is a relationship between the amount of training received by production line workers and the time it takes for them to troubleshoot a process problem. A sample of recently trained line workers was selected. The number of hours of training time received and the time it took (in minutes) for them to troubleshoot their last process problem were captured. Below are the scatterplot, regression results, and residual plots for these data. The regression equation is
Trouble Shooting =30.71.84= 30.7 - 1.84 Training
 Predictor  Coef  SE Coef  T  P  Constant 30.7291.02330.030.000 Training 1.83600.137613.350.000\begin{array} { l r r r r } \text { Predictor } & \text { Coef } & \text { SE Coef } & \text { T } & \text { P } \\ \text { Constant } & 30.729 & 1.023 & 30.03 & 0.000 \\ \text { Training } & - 1.8360 & 0.1376 & - 13.35 & 0.000 \end{array}
S=1.43588RSq=93.2 % RSq(adj)=92.7 % S = 1.43588 \quad \mathrm { R } - \mathrm { Sq } = 93.2 \text { \% } \quad \mathrm { R } - \mathrm { Sq } ( \mathrm { adj } ) = 92.7 \text { \% }
Analysis of Variance
 Source  DF  SS  MS  F  P  Regression 1367.20367.20178.100.000 Residual Error 1326.802.06 Total 14394.00\begin{array} { l r r r r r } \text { Source } & \text { DF } & \text { SS } & \text { MS } & \text { F } & \text { P } \\ \text { Regression } & 1 & 367.20 & 367.20 & 178.10 & 0.000 \\ \text { Residual Error } & 13 & 26.80 & 2.06 & & \\ \text { Total } & 14 & 394.00 & & & \end{array}
 Use the following for questions  An operations manager was interested in determining if there is a relationship between the amount of training received by production line workers and the time it takes for them to troubleshoot a process problem. A sample of recently trained line workers was selected. The number of hours of training time received and the time it took (in minutes) for them to troubleshoot their last process problem were captured. Below are the scatterplot, regression results, and residual plots for these data. The regression equation is Trouble Shooting  = 30.7 - 1.84  Training  \begin{array} { l r r r r } \text { Predictor } & \text { Coef } & \text { SE Coef } & \text { T } & \text { P } \\ \text { Constant } & 30.729 & 1.023 & 30.03 & 0.000 \\ \text { Training } & - 1.8360 & 0.1376 & - 13.35 & 0.000 \end{array}   S = 1.43588 \quad \mathrm { R } - \mathrm { Sq } = 93.2 \text { \% } \quad \mathrm { R } - \mathrm { Sq } ( \mathrm { adj } ) = 92.7 \text { \% }  Analysis of Variance  \begin{array} { l r r r r r } \text { Source } & \text { DF } & \text { SS } & \text { MS } & \text { F } & \text { P } \\ \text { Regression } & 1 & 367.20 & 367.20 & 178.10 & 0.000 \\ \text { Residual Error } & 13 & 26.80 & 2.06 & & \\ \text { Total } & 14 & 394.00 & & & \end{array}     -Write a sentence to interpret the coefficient of training in the regression equation.

-Write a sentence to interpret the coefficient of training in the regression equation.


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