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Approximately How Much Uranium (In Kg) Must Undergo Fission Per

question 51

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Approximately how much uranium (in kg) must undergo fission per day to provide 1 000 MW of power? (Assume an efficiency of 30%) . The nuclear reaction is Approximately how much uranium (in kg)  must undergo fission per day to provide 1 000 MW of power? (Assume an efficiency of 30%) . The nuclear reaction is   . m(n)  = 1.008 665 u M(U)  = 235.043 915 u M(Ba)  = 140.913 9 u M(Kr)  = 91.897 3 u U = 1.66 × 10−<sup>27</sup> kg A)  1.0 B)  3.5 C)  2.3 D)  4.6 E)  0.1 . m(n) = 1.008 665 u
M(U) = 235.043 915 u
M(Ba) = 140.913 9 u
M(Kr) = 91.897 3 u
U = 1.66 × 10−27 kg


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