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Based on the following thermochemical equations, what is the heat of vaporization of titanium(IV) chloride? Ti(s) + 2 Cl2(g) → TiCl4(l) ΔH = -804.2 kJ/mol
TiCl4(g) → 2 Cl2(g) + Ti(s) ΔH = 763.2 kJ/mol
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