Find Which Values of X Are Solutions $\sqrt { 16 - x ^ { 2 } } + 2 = 6$

question 166

Multiple Choice

Find which values of x are solutions.
- $\sqrt { 16 - x ^ { 2 } } + 2 = 6$
a. $x = 4$
b. $x = - 4$
c. $x = 0$

• A) (a) and (c)
• B) (a) and (b)
• C) (b)
• D) (c)

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