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Find the Angle Between the Given Vectors to the Nearest

question 22

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Find the angle between the given vectors to the nearest tenth of a degree.
- u=(3cosπ6) i+(3sinπ6) j,v=(cos4π3) i+(sin4π3) j\mathbf { u } = \left( 3 \cos \frac { \pi } { 6 } \right) \mathbf { i } + \left( 3 \sin \frac { \pi } { 6 } \right) \mathbf { j } , \mathbf { v } = \left( \cos \frac { 4 \pi } { 3 } \right) \mathbf { i } + \left( \sin \frac { 4 \pi } { 3 } \right) \mathbf { j }


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