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Provide an Appropriate Response 1+cot2θ=csc2θ1 + \cot ^ { 2 } \theta = \csc ^ { 2 } \theta

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Provide an appropriate response.
-A student claims: "Since 1+cot2θ=csc2θ1 + \cot ^ { 2 } \theta = \csc ^ { 2 } \theta , I should be able to also say 1+cotθ=cscθ1 + \cot \theta = \csc \theta if I take the square root of both sides." Comment on the student's statement.


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