Examlex

Solved

Prove the Identity cot⁡2xcsc⁡x−1=1+sin⁡xsin⁡x\frac { \cot ^ { 2 } x } { \csc x - 1 } = \frac { 1 + \sin x } { \sin x }

question 98

Essay

Prove the identity.
- cot⁡2xcsc⁡x−1=1+sin⁡xsin⁡x\frac { \cot ^ { 2 } x } { \csc x - 1 } = \frac { 1 + \sin x } { \sin x }

Definitions:

Related Questions

Q9: <span class="ql-formula" data-value="\sin \frac { 19 \pi

Q23: Quadrant III, sec t<br>A) Positive<br>B) Negative

Q46: <span class="ql-formula" data-value="\sin ^ { 2 }

Q72: <span class="ql-formula" data-value="\begin{array}{r}2 x+3 y \leq 6

Q87: <span class="ql-formula" data-value="\frac { 4 + 4

Q140: Given the SAS parts of a triangle,

Q189: <span class="ql-formula" data-value="\sec \theta"><span class="katex"><span class="katex-mathml"><math xmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><mi>sec</mi><mo>⁡</mo><mi>θ</mi></mrow><annotation

Q215: <span class="ql-formula" data-value="\sin \frac { \pi }

Q230: <img src="https://d2lvgg3v3hfg70.cloudfront.net/TB8181/.jpg" alt="

Q293: The path of a projectile fired