Find the Zeros of the Function in the Interval $[-2 \pi, 2 \pi]$

question 505

Multiple Choice

Find the zeros of the function in the interval $[-2 \pi, 2 \pi]$ .
- $$f ( x ) = - \frac { 1 } { 6 } \sin \frac { x } { 2 }$$

• A) \(0 , \pm 2 \pi\)
• B) \(0 , \pm \frac { \pi } { 2 } , \pm \pi\)
• C) \(\pm \frac { \pi } { 2 } , \pm \frac { 3 \pi } { 2 }\)
• D) \(0 , \pm \pi , \pm 2 \pi\)

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