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Solve for X in the Given Interval secx=2,3π2x2π\sec x = \sqrt { 2 } , \frac { 3 \pi } { 2 } \leq x \leq 2 \pi

question 120

Multiple Choice

Solve for x in the given interval.
- secx=2,3π2x2π\sec x = \sqrt { 2 } , \frac { 3 \pi } { 2 } \leq x \leq 2 \pi


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