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Solve for X in the Given Interval tanx=33,π2xπ\tan x = - \frac { \sqrt { 3 } } { 3 } , \frac { \pi } { 2 } \leq x \leq \pi

question 87

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Solve for x in the given interval.
- tanx=33,π2xπ\tan x = - \frac { \sqrt { 3 } } { 3 } , \frac { \pi } { 2 } \leq x \leq \pi

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