Solve the Problem $= 2 \pi \sqrt { 4.57142857 }$ Sec, Frequency

question 154

Multiple Choice

Solve the problem.
-Determine the period and frequency of oscillation when a pendulum of length 7 feet is released after being displaced 2 radians.

• A) Period \(= 2 \pi \sqrt { 4.57142857 }\) sec, frequency \(= \frac { 1 } { 2 \pi } \sqrt { 0.21875 }\) cycles per sec
• B) Period \(= 7 \pi \sec\), frequency \(= \frac { 1 } { 7 \pi }\) cycles per sec
• C) Period \(= 2 \pi \sqrt { 0.21875 } \mathrm { sec }\), frequency \(= \frac { 1 } { 2 \pi } \sqrt { 4.57142857 }\) cycles per sec
• D) Period \(= \frac { \pi } { 7 } \mathrm { sec }\), frequency \(= \frac { 7 } { \pi }\) cycles per sec

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