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Solve for X in the Given Interval secx=233,π2xπ\sec x = - \frac { 2 \sqrt { 3 } } { 3 } , \frac { \pi } { 2 } \leq x \leq \pi

question 213

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Solve for x in the given interval.
- secx=233,π2xπ\sec x = - \frac { 2 \sqrt { 3 } } { 3 } , \frac { \pi } { 2 } \leq x \leq \pi


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