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Solve the Problem f(x)=16.4e0.0002x\mathrm { f } ( \mathrm { x } ) = 16.4 \mathrm { e } ^ { 0.0002 \mathrm { x } }

question 74

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Solve the problem.
-In September 1998 the population of the country of West Goma in millions was modeled by f(x) =16.4e0.0002x\mathrm { f } ( \mathrm { x } ) = 16.4 \mathrm { e } ^ { 0.0002 \mathrm { x } } . At the same time the population of East Goma in millions was modeled by g(x) =13.7e0.0134xg ( x ) = 13.7 e ^ { 0.0134 x } . In both formulas x\mathrm { x } is the year, where x=0\mathrm { x } = 0 corresponds to September 1998. Assuming these trends continue, estimate the year when the population of West Goma will equal the population of East Goma.


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