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Solve the Problem 1.49×105Watts/m21.49 \times 10 ^ { - 5 } \mathrm { Watts } / \mathrm { m } ^ { 2 }

question 346

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Solve the problem.
-A certain noise produces 1.49×105Watts/m21.49 \times 10 ^ { - 5 } \mathrm { Watts } / \mathrm { m } ^ { 2 } of power. What is the decibel level of this noise? The level of sound intensity in decibels (dB) ( \mathrm { dB } ) is β=10log(I/I0) \beta = 10 \log \left( \mathrm { I } / \mathrm { I } _ { 0 } \right) , where β\beta (beta) is the number of decibels, I is the sound intensity in W/m2\mathrm { W } / \mathrm { m } ^ { 2 } , and I0=1012 W/m2\mathrm { I } _ { 0 } = 10 ^ { - 12 } \mathrm {~W} / \mathrm { m } ^ { 2 } . (Round to the nearest decibel.)


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