Determine the X Values That Cause the Polynomial Function to Be

question 222

Multiple Choice

Determine the x values that cause the polynomial function to be (a) zero, (b) positive, and (c) negative.
- $$f ( x ) = ( 5 x + 1 ) \left( x ^ { 2 } + 2 \right) ( x - 6 )$$

• A) (a) \(\left\{ - \frac { 1 } { 5 } , 6 \right\} ( b ) \left( - \frac { 1 } { 5 } , 6 \right)\) (c) \(\left( * , - \frac { 1 } { 5 } \right) \cup ( 6 , \infty )\)
• B) (a) \(\left\{ \frac { 1 } { 5 } , - 6 \right\}\) (b) \(\left( \cdots , - \frac { 1 } { 5 } \right) \cup ( 6 , \infty )\), (c) \(\left( - \frac { 1 } { 5 } , 6 \right)\)
• C) (a) \(\left\{ - \frac { 1 } { 5 } , 6 \right\} ( b ) \left( * , - \frac { 1 } { 5 } \right) \cup ( 6 , \infty ) , ( c ) \left( - \frac { 1 } { 5 } , 6 \right)\)
• D) (a) \(\left\{ - \frac { 1 } { 5 } , - 1,6 \right\}\) (b) \(\left( * , - \frac { 1 } { 5 } \right) \cup ( 6 , \infty )\), (c) \(\left( - \frac { 1 } { 5 } , 6 \right)\)

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