Determine the X Values That Cause the Function to Be $$f ( x ) = \frac { ( 2 x - 9 ) ( x + 3 ) } { x + 4 }$$

question 287

Multiple Choice

Determine the x values that cause the function to be (a) zero, (b) undefined, (c) positive, and (d) negative.
- $$f ( x ) = \frac { ( 2 x - 9 ) ( x + 3 ) } { x + 4 }$$

• A) (a) \(\left\{ - 3 , \frac { 9 } { 2 } \right\}\) (b) \(\{ - 4 \}\), (c) \(( \infty , - 4 ) \cup \left( - 3 , \frac { 9 } { 2 } \right)\), (d) \(( - 4 , - 3 ) \cup \left( \frac { 9 } { 2 } , \infty \right)\)
• B) (a) \(\{ - 4 \}\), (b) \(\left\{ - 3 , \frac { 9 } { 2 } \right\}\), (c) \(( - 4 , - 3 ) \cup \left( \frac { 9 } { 2 } , \infty \right)\), (d) \(( \infty , - 4 ) \cup \left( - 3 , \frac { 9 } { 2 } \right)\)
• C) (a) \(\left\{ - 3 , \frac { 9 } { 2 } \right\} (\) b \() \{ - 4 \} , \left( \right.\) c) \(( - 4 , - 3 ) \cup \left( \frac { 9 } { 2 } , \infty \right)\), (d) \(( \infty , - 4 ) \cup \left( - 3 , \frac { 9 } { 2 } \right)\)
• D) (a) \(\{ - 4 \}\), (b) \(\left\{ - 3 , \frac { 9 } { 2 } \right\}\), (c) \(( \infty , - 4 ) \cup \left( - 3 , \frac { 9 } { 2 } \right)\), (d) \(( - 4 , - 3 ) \cup \left( \frac { 9 } { 2 } , \infty \right)\)

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