Determine the X Values That Cause the Function to Be $$f ( x ) = \frac { 3 x - 4 } { ( x + 6 ) \sqrt { x - 5 } }$$

question 463

Multiple Choice

Determine the x values that cause the function to be (a) zero, (b) undefined, (c) positive, and (d) negative.
- $$f ( x ) = \frac { 3 x - 4 } { ( x + 6 ) \sqrt { x - 5 } }$$

• A) (a) \(\varnothing\), (b) \((\infty , 5 )\), (c) \(\varnothing\), (d) \(( 5 , \infty )\)
• B) (a) \(\left\{ \frac { 4 } { 3 } \right\} \left( \right.\) b) \(\{ - 6,5 \}\), (c) \(\left( - 6 , \frac { 4 } { 3 } \right) \cup \left( \frac { 5 } { 3 } , \infty \right)\), (d) \((\infty , - 6 ) \cup \left( \frac { 4 } { 3 } , 5 \right)\)
• C) (a) \(\varnothing\), (b) \(( - 5,5 )\), (c) \(( 5 , \infty )\), (d) \(\varnothing\)
• D) (a) \(\left\{ \frac { 4 } { 3 } \right\}\) (b) \(\{ - 6,5 \} , \left( \right.\) c) \(( - , - 6 ) \cup \left( \frac { 4 } { 3 } , 5 \right)\), (d) \(\left( - 6 , \frac { 4 } { 3 } \right) \cup \left( \frac { 5 } { 3 } , \infty \right)\)

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