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Solve the Problem 32 m/sec32 \mathrm {~m} / \mathrm { sec }

question 168

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Solve the problem.
-A rock is thrown vertically upward from the surface of the moon at a velocity of 32 m/sec32 \mathrm {~m} / \mathrm { sec } . The graph shows the height yy of the rock, in meters, after xx seconds. Estimate and interpret the turning point (the point at which the graph reaches its maximum value) .
 Solve the problem. -A rock is thrown vertically upward from the surface of the moon at a velocity of  32 \mathrm {~m} / \mathrm { sec } . The graph shows the height  y  of the rock, in meters, after  x  seconds. Estimate and interpret the turning point (the point at which the graph reaches its maximum value) .    A)  The turning point is at approximately  ( 40,320 )  . This is the point at which the rock reaches its maximum height and starts to fall back towards the surface of the moon. B)  The turning point is at approximately  ( 20,320 )  . This is the point at which the rock reaches its maximum height and starts to fall back towards the surface of the moon. C)  The turning point is at approximately  ( 40,0 )  . This is the point at which the rock reaches the surface of the moon again. D)  The turning point is at approximately  ( 20,320 )  . This is the point at which the rock reaches its maximum velocity and starts to slow down.


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