What Is the Disintegration Energy (In MeV) Associated with This ${ }_{60}^{144} \mathrm{Nd} \rightarrow{ }_{58}^{140} \mathrm{Ce}+{ }_{2}^{4} \mathrm{He}$

question 20

Multiple Choice

What is the disintegration energy (in MeV) associated with this spontaneous decay? ${ }_{60}^{144} \mathrm{Nd} \rightarrow{ }_{58}^{140} \mathrm{Ce}+{ }_{2}^{4} \mathrm{He}$ mNd = 143.910083 u mCe = 139.905434 u
MHe = 4.002603 u
1 u = 1.66 * 10-27 kg

• A)1.54
• B)2.37
• C)1.90
• D)4.13
• E)8.21

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