Approximately How Much Uranium (In Kg) Must Undergo Fission Per

question 41

Multiple Choice

Approximately how much uranium (in kg) must undergo fission per day to provide 1000 MW of power? (Assume an efficiency of 30%) .The nuclear reaction is: . m(n) = 1.008665 u
M(U) = 235.043915 u
M(Ba) = 140.9139 u
M(Kr) = 91.8973 u
U = 1.66 * 10^-27 kg

• A)1.0
• B)3.5
• C)2.3
• D)4.6
• E)0.1

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