The Rotational Kinetic Energy of a Diatomic Molecule Can Take $\omega$

question 27

Multiple Choice

The rotational kinetic energy of a diatomic molecule can take the form:

• A)(1/2)m \( \omega \)2
• B)(1/2)I \( \omega \)2
• C)[m1m2/(m1 + m2)]r2 \( \omega \)2
• D)(1/2)mv2
• E)1/2 \(\mu\) \( \omega \)2

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