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Knowing That g=9.80 m s2g=9.80 \frac{\mathrm{~m}}{\mathrm{~s}^{2}} At Sea Level and That RE = 6

question 44

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Knowing that g=9.80 m s2g=9.80 \frac{\mathrm{~m}}{\mathrm{~s}^{2}} at sea level and that RE = 6.37 * 106 m, we find that the value of g in m s2\frac{\mathrm{m}}{\mathrm{~s}^{2}} at a distance RE from the surface of the Earth is:


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