Knowing That $g=9.80 \frac{\mathrm{~m}}{\mathrm{~s}^{2}}$ At Sea Level and That RE = 6

question 44

Multiple Choice

Knowing that $g=9.80 \frac{\mathrm{~m}}{\mathrm{~s}^{2}}$ at sea level and that RE = 6.37 * 106 m, we find that the value of g in $\frac{\mathrm{m}}{\mathrm{~s}^{2}}$ at a distance RE from the surface of the Earth is:

• A)1.23.
• B)2.45.
• C)4.90.
• D)7.35.
• E)9.80.

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Definitions:

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