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A 30-Kg Particle Has a Position Vector Given By By \overrightarrow{\mathbf{r}}=\left(2.0

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A 3.0-kg particle has a position vector given by r=(2.0t2i^+3.0j^) \overrightarrow{\mathbf{r}}=\left(2.0 t^{2} \hat{\mathbf{i}}+3.0 \hat{\mathbf{j}}\right) where r\overrightarrow{\mathbf{r}} is in metres and t is in seconds. What is the angular momentum of the particle, in kg.m2/s, about the origin at t = 2 s?


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