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The Position of an Object Is Given By r=(4.00ti^+6.00t3j^)m\overrightarrow{\mathbf{r}}=\left(-4.00 t \hat{\mathbf{i}}+6.00 t^{3} \hat{\mathbf{j}}\right) \mathrm{m}

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The position of an object is given by r=(4.00ti^+6.00t3j^) m\overrightarrow{\mathbf{r}}=\left(-4.00 t \hat{\mathbf{i}}+6.00 t^{3} \hat{\mathbf{j}}\right) \mathrm{m} where t is in seconds. At t = 2.0 s, what is the magnitude of the particle's acceleration?


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