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Find an Equation of the Tangent Line to the Graph 7x22xy+4y236=0,(2,1)7 x ^ { 2 } - 2 x y + 4 y ^ { 2 } - 36 = 0 , \quad ( 2 , - 1 )

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Find an equation of the tangent line to the graph of the function given below at the given point. 7x22xy+4y236=0,(2,1) 7 x ^ { 2 } - 2 x y + 4 y ^ { 2 } - 36 = 0 , \quad ( 2 , - 1 ) (The coefficients below are given to two decimal places.)


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