Per Second And $\theta$ Is the Angle of Elevation $v _ { 0 } = 2300$

question 42

Multiple Choice

$\text { The range } R \text { of a projectile is } R = \frac { v _ { 0 } ^ { 2 } } { 32 } ( \sin 2 \theta ) \text { where } v _ { 0 } \text { is the initial velocity in feet }$ per second and $\theta$ is the angle of elevation. If $v _ { 0 } = 2300$ feet per second and $\theta$ is changed from $13 ^ { \circ }$ to $14 ^ { \circ }$ use differentials to approximate the change in the range. Round your answer to the nearest integer.

• A) \(2,593 \mathrm { ft }\)
• B) \(4,568 \mathrm { ft }\)
• C) \(5,623 \mathrm { ft }\)
• D) \(2,811 \mathrm { ft }\)
• E) \(5,186 \mathrm { ft }\)

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