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 The force F (in newtons) of a hydraulic cylinder in a press is proportional to the \text { The force } F \text { (in newtons) of a hydraulic cylinder in a press is proportional to the }

question 48

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 The force F (in newtons)  of a hydraulic cylinder in a press is proportional to the \text { The force } F \text { (in newtons) of a hydraulic cylinder in a press is proportional to the } square of secx\sec x where xx is the distance (in meters) that the cylinder is extended in its cycle. The domain of FF is [0,π/3][ 0 , \pi / 3 ] and F(0) =400F ( 0 ) = 400 . Find the average force exerted by the press over the interval [0,π/3][ 0 , \pi / 3 ] . Round your answer to the nearest whole number.


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