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The Height Above the Ground of an Object Thrown Upward f(t)=16t2+v0t+s0f ( t ) = - 16 t ^ { 2 } + v _ { 0 } t + s _ { 0 }

question 155

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The height above the ground of an object thrown upward from a point feet above the ground with an initial velocity of feet per second is given by the function f(t) =16t2+v0t+s0f ( t ) = - 16 t ^ { 2 } + v _ { 0 } t + s _ { 0 } . A balloon, rising vertically with a velocity of 24 feet per second, releases a sandbag at the instant it is 20 feet above the ground. At what velocity will it hit the ground? Round your answer to three decimal places.


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