$t = \frac { 10 } { \ln 2 } \int _ { 250 } ^ { 340 } \frac { 1 } { T - 70 } d T$

question 56

Multiple Choice

$\text { Find the time required for an object to cool from } 340 ^ { \circ } \mathrm { F } \text { to } 250 ^ { \circ } \mathrm { F } \text { by evaluating }$ $t = \frac { 10 } { \ln 2 } \int _ { 250 } ^ { 340 } \frac { 1 } { T - 70 } d T$ , where $t$ is time in minutes. Round your answer to four decimal places.

• A) \(6.4346\) minutes
• B) \(4.4251\) minutes
• C) \(3.6907\) minutes
• D) \(4.0598\) minutes
• E) \(5.8496\) minutes

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