Match the Logistic Equation and Initial Condition with the Graph$\frac { d y } { d t } = 2 y \left( 1 - \frac { y } { 14 } \right) , y ( 0 ) = 18$

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The Answer of Match the Logistic Equation and Initial Condition with the Graph$\frac { d y } { d t } = 2 y \left( 1 - \frac { y } { 14 } \right) , y ( 0 ) = 18$

Match the Logistic Equation and Initial Condition with the Graph $\frac { d y } { d t } = 2 y \left( 1 - \frac { y } { 14 } \right) , y ( 0 ) = 18$

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Match the Logistic Equation and Initial Condition with the Graph dydt=2y(1−y14),y(0)=18\frac { d y } { d t } = 2 y \left( 1 - \frac { y } { 14 } \right) , y ( 0 ) = 18dtdy​=2y(1−14y​),y(0)=18

Definitions:

Match the Logistic Equation and Initial Condition with the Graph $\frac { d y } { d t } = 2 y \left( 1 - \frac { y } { 14 } \right) , y ( 0 ) = 18$