Neglecting Air Resistance and the Weight of the Propellant, Determine $5.07 \times 10 ^ { 10 } \mathrm { ft } - \mathrm { lb }$

question 25

Multiple Choice

Neglecting air resistance and the weight of the propellant, determine the work done in propelling a six-ton satellite to a height of 200 miles above earth. Assume that Earth has a radius of 4000 miles.

• A) \(5.07 \times 10 ^ { 10 } \mathrm { ft } - \mathrm { lb }\)
• B) \(6.03 \times 10 ^ { 9 } \mathrm { ft } - \mathrm { lb }\)
• C) \(1.21 \times 10 ^ { 12 } \mathrm { ft } - \mathrm { b }\)
• D) \(1.21 \times 10 ^ { 10 } \mathrm { ft } - \mathrm { lb }\)
• E) \(5.07 \times 10 ^ { 12 } \mathrm { ft } - \mathrm { lb }\)

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