Use Substitution and Partial Fractions to Find the Indefinite Integral $\int \frac { \sqrt { x } } { x - 25 } d x$

question 12

Multiple Choice

Use substitution and partial fractions to find the indefinite integral.
$\int \frac { \sqrt { x } } { x - 25 } d x$

• A)
• \(\int \frac { \sqrt { x } } { x - 25 } d x = 5 \log ( 5 - \sqrt { x } ) - 4 \log ( \sqrt { x } - 5 ) + C\)
• B)
• \(\int \frac { \sqrt { x } } { x - 25 } d x = \sqrt { x } + \log ( 5 - \sqrt { x } ) - 4 \log ( \sqrt { x } - 5 ) + C\)
• C)
• \(\int \frac { \sqrt { x } } { x - 25 } d x = 2 \sqrt { x } + \log ( 1 - \sqrt { x } ) + C\)
• D)
• \(\int \frac { \sqrt { x } } { x - 25 } d x = 2 \sqrt { x } + x ^ { 2 } + 5 \log ( 5 - \sqrt { x } ) - 4 \log ( \sqrt { x } - 5 ) + C\)
• E)
• \(\int \frac { \sqrt { x } } { x - 25 } d x = 2 \sqrt { x } + 5 \log ( 5 - \sqrt { x } ) - 4 \log ( \sqrt { x } - 5 ) + C\)

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