Solve $$y ^ { t } = \tan ^ { 3 } 3 x \sec 3 x$$

question 40

Multiple Choice

Solve. $$y ^ { t } = \tan ^ { 3 } 3 x \sec 3 x$$

• A) \(y = \frac { 1 } { 6 } \sec ^ { 3 } 3 x - \frac { 1 } { 4 } \sec 3 x + C\)
• B) \(y = \frac { 1 } { 9 } \sec ^ { 2 } 3 x - \frac { 1 } { 4 } \sec 3 x + C\)
• C) \(y = \frac { 1 } { 6 } \sec ^ { 2 } 3 x + \frac { 1 } { 3 } \sec 3 x + C\)
• D) \(y = \frac { 1 } { 9 } \sec ^ { 3 } 3 x - \frac { 1 } { 3 } \sec 3 x + C\)
• E) \(y = \frac { 1 } { 9 } \sec ^ { 3 } 3 x + \frac { 1 } { 3 } \sec 3 x + C\)

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