Use a Table of Integrals to Find the Integral $\int \frac { \sqrt { 49 - x ^ { 4 } } } { x } d x$

question 103

Multiple Choice

Use a table of integrals to find the integral. $\int \frac { \sqrt { 49 - x ^ { 4 } } } { x } d x$

• A)
• \[\int \frac { \sqrt { 49 - x ^ { 4 } } } { x } d x = \frac { 1 } { 2 } \left[ \sqrt { 49 - x ^ { 4 } } - 7 \log \left( \sqrt { 49 - x ^ { 4 } } + 7 \right) + 49 \log \left( x ^ { 2 } \right) \right] + C\]
• B)
• \[\int \frac { \sqrt { 49 - x ^ { 4 } } } { x } d x = \frac { 1 } { 2 } \left[ \sqrt { 49 - x ^ { 4 } } - 7 \log \left( \sqrt { 49 - x ^ { 4 } } + 7 \right) + 7 \log \left( x ^ { 2 } \right) \right] + C\]
• C)
• \[\int \frac { \sqrt { 49 - x ^ { 4 } } } { x } d x = \frac { 1 } { 2 } \left[ \sqrt { 49 - x ^ { 4 } } - 49 \log \left( \sqrt { 49 - x ^ { 4 } } + 7 \right) + 7 \log \left( x ^ { 2 } \right) \right] + C\]
• D)
• \[\int \frac { \sqrt { 49 - x ^ { 4 } } } { x } d x = \frac { 1 } { 2 } \left[ \sqrt { 49 - x ^ { 4 } } - \log \left( \sqrt { 49 - x ^ { 4 } } + 1 \right) + 7 \log \left( x ^ { 2 } \right) \right] + C\]
• E)
• \[\int \frac { \sqrt { 49 - x ^ { 4 } } } { x } d x = \frac { 1 } { 2 } \left[ \sqrt { 49 - x ^ { 4 } } - 7 \log \left( \sqrt { 49 - x ^ { 4 } } + 1 \right) + 7 \log \left( x ^ { 2 } \right) \right] + C\]

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