$\text { State where the power series } \sum _ { n = 1 } ^ { \infty } \frac { ( x - 2 ) ^ { n } } { n ^ { 3 } } \text { is centered. }$

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The Answer of $\text { State where the power series } \sum _ { n = 1 } ^ { \infty } \frac { ( x - 2 ) ^ { n } } { n ^ { 3 } } \text { is centered. }$

State where the power series ∑n=1∞(x−2)nn3 is centered. \text { State where the power series } \sum _ { n = 1 } ^ { \infty } \frac { ( x - 2 ) ^ { n } } { n ^ { 3 } } \text { is centered. } State where the power series ∑n=1∞​n3(x−2)n​ is centered.