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Find the Area of the Surface Formed by Revolving About r=6cosθ,0θπ2r = 6 \cos \theta , 0 \leq \theta \leq \frac { \pi } { 2 }

question 36

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Find the area of the surface formed by revolving about the polar axis the following curve over the given interval. r=6cosθ,0θπ2r = 6 \cos \theta , 0 \leq \theta \leq \frac { \pi } { 2 }


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