Identify Equilibrium Values and Determine Which Are Stable and Which $$\frac { d y } { d x } = ( y + 2 ) ( y + 1 )$$

question 18

Multiple Choice

Identify equilibrium values and determine which are stable and which are unstable.
- $$\frac { d y } { d x } = ( y + 2 ) ( y + 1 )$$

• A) \(y = - 1\) is a stable equilibrium value and \(y = 2\) is an unstable equilibrium.
• B) \(y = 2\) is a stable equilibrium value and \(y = 1\) is an unstable equilibrium.
• C) \(y = - 2\) is a stable equilibrium value and \(y = 1\) is an unstable equilibrium.
• D) \(y = 1\) is a stable equilibrium value and \(y = - 2\) is an unstable equilibrium.

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