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Solve the Problem a=d2s/dt2=(5/t)+9ta = d ^ { 2 } s / d t ^ { 2 } = ( 5 / \sqrt { t } ) + 9 \sqrt { t }

question 149

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Solve the problem.
-A particle moves on a coordinate line with acceleration a=d2s/dt2=(5/t) +9ta = d ^ { 2 } s / d t ^ { 2 } = ( 5 / \sqrt { t } ) + 9 \sqrt { t } , subject to the conditions that ds/dt=3\mathrm { ds } / \mathrm { dt } = 3 and s=1\mathrm { s } = 1 when t=1\mathrm { t } = 1 . Find the velocity v=ds/dt\mathrm { v } = \mathrm { ds } / \mathrm { dt } in terms of t\mathrm { t } and the position ss in terms of tt .


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